Worked example
Factorise \(3x^2+10x-8\)
- Guide number: \((ax^2)(c)=(3x^2)(-8)=-24x^2\).
- Choose factors of the guide number that sum to 10x: \((-2x)+(12x)=10x\).
- Place \(3x^2,\ 12x,\ -2x,\ -8\) into the grid and take HCFs.
\(x\)
\(+4\)
\(3x\)
\(3x^2\)
\(12x\)
\(-2\)
\(-2x\)
\(-8\)
Hence \((3x-2)(x+4)\).
Solve \(3x^2+10x-8=0\)
\((3x-2)(x+4)=0 \Rightarrow x=\dfrac{2}{3}\) or \(x=-4\).